Propability: Somebodys mistake

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Homework Help Overview

The discussion revolves around a probability problem involving Bayes' theorem, specifically related to extracting a black ball from one of five boxes containing varying numbers of white and black balls. Participants are examining the initial probabilities assigned to each box and questioning the accuracy of these values as presented in the problem statement.

Discussion Character

  • Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Some participants are questioning the initial probabilities assigned to the boxes, particularly the value of p(h2). Others are seeking clarification on the notation used, such as what h1, h2, h3, and 'a' represent in the context of the problem.

Discussion Status

There is an ongoing exploration of the definitions and values presented in the problem. Some participants express confusion regarding the notation and the implications of the probabilities, while others suggest that there may be a typographical error in the problem statement. No consensus has been reached on the correct interpretation or values.

Contextual Notes

Participants note that the problem as presented in the book may contain inconsistencies, particularly regarding the probabilities assigned to the boxes. There is also a mention of the difficulty in understanding the mathematical language used in the problem.

lorik
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Homework Statement


bayes theorem
we got 5 boxes with white and black balls ,2 boxes have 2 white balls and 3 black, 2 boxes have 1 white and 4 black , 1 box has 4 whites and 1black .From a random extraction the ball turned out to be black find propability that the extracted ball was from the second box

p(h1)=2/5 ,p(h2)=2/5, p(h3)=1/5 ,p(h1)a=3/5,P(h2)a=4/5,p(h3)a=1/5

This is the way its written in the book and professor tought us as its written in the book

Now I know how it goes but I think there might be a problem in the book because p(h2) is not really 2/5 but it should 1/5

am I correct or I have misunderstood all this problem ?
 
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At first I thought it is a typo, but you are consistent in all your threads.

Probability.
 
lorik said:

Homework Statement


bayes theorem
we got 5 boxes with white and black balls ,2 boxes have 2 white balls and 3 black, 2 boxes have 1 white and 4 black , 1 box has 4 whites and 1black .From a random extraction the ball turned out to be black find propability that the extracted ball was from the second box

p(h1)=2/5 ,p(h2)=2/5, p(h3)=1/5 ,p(h1)a=3/5,P(h2)a=4/5,p(h3)a=1/5
What do h1, h2, and h3 mean? What is a?
lorik said:
This is the way its written in the book and professor tought us as its written in the book

Now I know how it goes but I think there might be a problem in the book because p(h2) is not really 2/5 but it should 1/5

am I correct or I have misunderstood all this problem ?
 
Borek said:
At first I thought it is a typo, but you are consistent in all your threads.

Probability.


my tongue language I think pronounces p instead of b .I have the book right here let me check...wait a sec the book actually writes 'b' as well .Anywayz
 
Mark44 said:
What do h1, h2, and h3 mean? What is a?

I think it must 'the happening or event' I don't know I hate learning literature related to math.
 
It's impossible to determine the probability of an event if you don't know what the event is.

Also, what is a?
lorik said:
p(h1)a=3/5,P(h2)a=4/5,p(h3)a=1/5
 
Mark44 said:
It's impossible to determine the probability of an event if you don't know what the event is.

Also, what is a?

Sorry , the way it should be done is : ph1(A)=3/5, ph2(A)=4/5 ,ph3(A)=1/5

p(h1)=2/5 2 white balls ,ph1(A)= 3/5, 3 white balls all boxes equal 5 so...
 
lorik said:
Sorry , the way it should be done is : ph1(A)=3/5, ph2(A)=4/5 ,ph3(A)=1/5

p(h1)=2/5 2 white balls ,ph1(A)= 3/5, 3 white balls all boxes equal 5 so...

I don't understand ph1(A), ph2(A), or ph3(A) either, and you still haven't explained what A is.

Probabilities are usually written as P(some event). A typical example is when we flip a coin. One side is called the head side, and the other is the tail side. If we disallow the possibility of the coin landing on its edge, the two probabilities are P(H) and P(T), and each probability is 1/2 for a fair coin.
 

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