Proposition needed to be proven

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Werg22
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A relatively lengthy proof I am writing for an assignment leads me to a proposition (which I need to turn into a lemma for the proof to be complete) conjecturing that for any [tex]n \in \mathbb{Z^{*}}[/tex], there are no [tex]a, b, c \in \mathbb{Z^{*}}[/tex] such that [tex]4n + 3 = 5^{a}13^{b}17^{c}[/tex]. I haven't been able to find to tackle the problem, any suggestions?
 
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I don't understand you question...do you mean that the sequence defined by [tex]a_n = 4n +3 , n \in \mathbb{Z}[/tex] must generate some primes for n other than 5, 13, 17 and 21?

The digits 4 and 3 add up to 7, a prime. So a value of n that would keep the digits the same already rules the number out for a heap of divisibility tests for small numbers. Since it only rules out small numbers, try small values of n. n=1, a_1 = 7, prime. n=10, a_10 = 43, prime.

I don't think that's what you are asking, because I'm sure you would have spotted n=1 straight away.
 
Sorry for stating that 21 is prime, it was 4 am here, easy to say gibberish at this time. That said, I have rectified the original question, so please read it.
 
(4n+1)(4k+1) = 16nk+4(n+k)+1 = 4m+1. The form is preserved under multiplication.
 
Thanks allot, the proof is complete. :smile:
 
Sorry to sound ignorant but what does the "*" represent in [tex]\mathbb{Z}^{*}[/tex]
 
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uart said:
Sorry to sound ignorant but what does the "*" represent in [tex]\mathbb{Z}^{*}[/tex]

Non-negative integers.
 
I'm curious as to why you ask this question, Werg22. I vaguely remember using/reading this lemma, as proven by robert Ihnot here, in a maths book. It was titled "Proofs from the BOOK" or something along those lines. I believe the chapter I found it in was something on the representation of integers as sum of primes or something like that.