Proton NMR: why does this appear as a multiplet?

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SUMMARY

The discussion focuses on understanding the concept of multiplets in Proton NMR, specifically regarding the shifts and nature of protons in a given molecule. The participant expresses confusion about why a specific carbon (C) appears as a multiplet, despite having two doublet protons and one single proton. The terms "doublet of triplets" and "triplet of doublets" are used to describe the expected splitting patterns. Additionally, the participant questions why another carbon (D) does not exhibit multiplet behavior.

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  • Understanding of Proton NMR spectroscopy
  • Knowledge of splitting patterns in NMR (e.g., doublets, triplets)
  • Familiarity with the concept of coupling constants
  • Basic grasp of molecular structure and proton environments
NEXT STEPS
  • Study the principles of NMR spectroscopy, focusing on multiplet formation
  • Learn about coupling constants and their role in determining splitting patterns
  • Explore examples of complex splitting patterns in Proton NMR
  • Review molecular structures to identify proton environments that lead to multiplets
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Chemistry students, researchers in organic chemistry, and anyone studying NMR spectroscopy who seeks to deepen their understanding of proton multiplet analysis.

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Homework Statement



It asks you to identify the shift and nature of the protons in the molecule.

Picture:

https://mailhost-6.tamu.edu/service/home/~/?auth=co&id=24393&part=2

multiplet.gif


Homework Equations



none

The Attempt at a Solution



I cannot understand what makes C a multiplet. I suppose I am confused about the concept of a multiplet in general.
 
Last edited:
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Sorry, no picture.
 
sorry. what about now?
 
Mitocarta said:
I cannot understand what makes C a multiplet.

Two d protons and single b proton. Together they should yield doublet of triplets (or triplet of doublets).
 
Borek said:
Two d protons and single b proton. Together they should yield doublet of triplets (or triplet of doublets).

why is D not a multiplet ?
 

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