Prove A^-1=(A^T A)^-1 A^T (matrices)

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SUMMARY

The equation A^-1 = (A^T A)^-1 A^T is proven for a general, non-singular matrix A. The proof utilizes the property that the inverse of a product is the product of the inverses in reverse order. By applying this property, it is demonstrated that multiplying (A^T A)^-1 by A^T and then by A results in the identity matrix, confirming the validity of the equation. This proof is essential for understanding matrix inverses in linear algebra.

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blueyellow
For a general, non-singular matrix A prove that

A^-1=[(A^T A)^-1] A^T


The Attempt at a Solution


tried searching in textbook and internet-nothing yet
someone somewhere must know an easy way to do this without having to sit there for five hours getting stuck
but i just look at this and i dnt even kno how to start
thanks in advance
 
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The inverse of a product is the product of the inverses in reverse order.
 
((a^t a)^{-1}) a^t = ((a^t a)^{-1}) a^t ((a a^{-1}) = ((a^t a)^{-1}) (a^t a) a^{-1} = i a^{-1} = a^{-1}

[EDIT]For some unknown reason the forum translated A, T and I into lowercase letters.
Well, I hope you catch the drift.[/EDIT]
 

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