Prove AB=2CE | Geometry Problem

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In the figure attached, I have to prove AB=2CE given that: line AC is parallel to DE and angles as mentioned in the figure. Can anyone please help me to prove the same?
 

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Calculate angles of the triangle ##CDE## in terms of ##\angle BAC## Then use the sine formula to relate ##|CE|## to ##|CD|##
 
∠BAC can vary and so will the angles of the Triangle CDE
 
rushikesh said:
∠BAC can vary and so will the angles of the Triangle CDE

They can. But they're related, so you can express one in terms of the other.