Are Eigenvalues of a Non-Hermitian Matrix Real?

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Eigenvalues of a non-Hermitian matrix are generally complex, and proving they are real without computation is challenging. The discussion seeks a method analogous to the Hermitian case, where real eigenvalues are guaranteed. However, no definitive criteria exist for non-Hermitian matrices that ensure real eigenvalues without calculation. Ultimately, the consensus is that computing the eigenvalues remains the most reliable approach. The topic highlights the complexities of eigenvalue properties in non-Hermitian matrices.
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Given a 4x4 non-Hermitian matrix, is there any method I can use to prove the eigenvalues are real, aside from actually computing them?

I'm looking for something like the converse of the statement "M is Hermitian implies M has real eigenvalues".

When can one say that the eigenvalues of a given matrix are real?
 
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In general, the eigenvalues of a non-Hermitian matrix can be complex. You would need to compute them.
 
OK, I'm not surprised. Thanks anyways.
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

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