Prove Identity: (1+sin(x))/(1-sin(x))=2tan^2(x)+1+2tan(x)sec(x)

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Discussion Overview

The discussion revolves around proving the trigonometric identity (1+sin(x))/(1-sin(x))=2tan^2(x)+1+2tan(x)sec(x). Participants explore methods to manipulate the left-hand side of the equation to match the right-hand side, focusing on algebraic techniques.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses difficulty in proving the identity and seeks assistance.
  • Another participant suggests starting with the left-hand side and proposes using the conjugate to eliminate the denominator.
  • A participant shares their working and asks for confirmation of their approach.
  • A later reply provides positive feedback on the approach taken.

Areas of Agreement / Disagreement

The discussion appears to be collaborative, with participants agreeing on the initial approach to manipulate the expression, but no consensus on the overall proof has been reached yet.

Contextual Notes

Participants have not yet resolved the identity, and the discussion remains focused on the manipulation of the left-hand side without confirming the equivalence to the right-hand side.

Sean1
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I cannot seem to prove the following identity

(1+sin(x))/(1-sin(x))=2tan^2(x)+1+2tan(x)sec(x)

Can you assist?
 
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Hi Sean,

Let's start with the left-hand side.

$$\frac{1+\sin(x)}{1-\sin(x)}$$.

We want this to turn into an expression without a fraction, so maybe we can try getting rid of the denominator somehow. When I see something in the form of $a-b$, I often try multiplying by the conjugate $a+b$.

$$\frac{1+\sin(x)}{1-\sin(x)} \left( \frac{1+\sin(x)}{1+\sin(x)} \right) $$

What do you get after trying this?
 
Thanks for getting me started.

This is my working. Can you confirm my approach is correct?

View attachment 4467
 

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Last edited:
Looks good! :)
 

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