Prove Injectivity & Surjectivity of Composite Application f

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The discussion centers on proving the injectivity and surjectivity of a composite application function f from a non-empty set E to itself, under the condition that f∘f∘f = f. It is established that f is an injection if and only if f is a surjection. The proof involves demonstrating that if f is an injection, then for all elements e in E, f(f(e)) equals e, confirming surjectivity. Conversely, if f is a surjection and f(x) equals f(y), it follows that x equals y, establishing injectivity.

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Let f be an application from E to E (E≠∅) such that f∘f∘f = f
Prove f is an injection ⇔ f is a surjection


I honestly have no idea how to start and I'd love to know the answer before my math exam tomorrow morning (Thinking)
 
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Suppose $f$ is an injection. Show that for all $e\in E$, $f(f(e))= e$. This will prove $f$ is a surjection.

Now suppose $f$ is a surjection and $f(x) = f(y)$. Let $z,w\in E$ such that $f(z) = x$ and $f(w) = y$. Then $$x = f(z) = f(f(f(z))) = f(f(x)) = f(f(y)) = f(f(f(w))) = f(w) = y $$

Hence, $f$ is an injection.
 
Hello Euge ,
I never would've thought of that ,thank you so much for your help !
 

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