b00tofuu Messages 11 Reaction score 0 Thread starter Dec 19, 2009 #1 suppose v1,...,vk are nonzero vectors with the property that vi.vj=0 whenever i is not equal to j. Prove that {v1,...,vk} is linearly independent.
suppose v1,...,vk are nonzero vectors with the property that vi.vj=0 whenever i is not equal to j. Prove that {v1,...,vk} is linearly independent.
rochfor1 Messages 256 Reaction score 0 Dec 19, 2009 #2 Suppose [tex]\alpha_1, \ldots, \alpha_k[/tex] are such that [tex]0 = \alpha_1 v_1 + \ldots + \alpha_k v_k[/tex]. Try taking the dot product of this equation with each of the [tex]v_i[/tex]s and see what it tells you about the [tex]\alpha_i[/tex]s.
Suppose [tex]\alpha_1, \ldots, \alpha_k[/tex] are such that [tex]0 = \alpha_1 v_1 + \ldots + \alpha_k v_k[/tex]. Try taking the dot product of this equation with each of the [tex]v_i[/tex]s and see what it tells you about the [tex]\alpha_i[/tex]s.