Prove \mathbb Z^{+} X \: \mathbb Z^{+} X \: \mathbb Z^{+} is Countable

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SUMMARY

The discussion centers on proving that the Cartesian product \(\mathbb{Z}^{+} \times \mathbb{Z}^{+} \times \mathbb{Z}^{+}\) is countable. Participants suggest demonstrating a bijection between \(\mathbb{Z} \times \mathbb{Z}\) and \(\mathbb{N}\) to establish countability. A specific bijection function, \(f(a,b) = 2^{a-1}(2b-1)\), is proposed to show that \(\mathbb{Z}^{+} \times \mathbb{Z}^{+}\) is one-to-one and onto, thereby confirming its countability. The conversation highlights the need for foundational knowledge in abstract algebra to tackle such proofs effectively.

PREREQUISITES
  • Understanding of countable sets and bijections
  • Familiarity with Cartesian products in set theory
  • Basic knowledge of functions and mappings
  • Experience with proof techniques in mathematics
NEXT STEPS
  • Study the concept of countable vs uncountable sets in set theory
  • Learn how to construct bijections between sets
  • Explore the properties of Cartesian products in more depth
  • Review proof techniques used in abstract algebra
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Mathematics students, particularly those studying set theory and abstract algebra, as well as educators seeking to enhance their understanding of countability concepts.

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Homework Statement


Prove that \mathbb Z^{+} X \: \mathbb Z^{+} X \: \mathbb Z^{+} is countable, where X is the Cartesian product.

Homework Equations


The Attempt at a Solution


I'm lost as to where to start proving this.
 
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The Captain said:

Homework Statement


Prove that \mathbb Z^{+} X \: \mathbb Z^{+} X \: \mathbb Z^{+} is countable, where X is the Cartesian product.


Homework Equations





The Attempt at a Solution


I'm lost as to where to start proving this.

do you know how to prove this

\mathbb Z^{+} X \: \mathbb Z^{+}

is countable?
 
There are many ways to do this you show that there it bijection from N to ZxZ ,that is , ZxZ is countable. Then show that there is bijection from ZxZ to ZxZxZ.

EDIT
someone beat me to it.
 
I had to prove that \mathbb Z^{+} \: X \: Z^{+} \: \rightarrow \: Z^{+} was one-one and onto using f(a,b)=2^{a-1}(2b-1), does that count for proving it's countable, and if it's not, no I don't know how to prove it's countable.

The class I'm taking is a giant leap from Calc 4, and Abstract Algebra isn't even pre-req though it probably should be because the professor keeps asking who's taking it before.
 
Yes, that is a bijection. So you have already shown the first part all you need to do provide a bijection from ZxZxZ to ZxZ .
 

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