Prove or disprove (n+π/2)+nπ=(2n+1/2)π

[Tilted]

Homework Statement

Prove or disprove the following equation.

(n+$\pi$/2)+n$\pi$=(2n+1/2)$\pi$

n=0,1,2,3...

Homework Equations

None.

The Attempt at a Solution

I have simplified the equation to this form, I just need help proving it.

Thanks in advance.

 

[PAllen]

I suspect you have erred in what you didn't show us. Anyway, what do think happens if you let n=1?

 

[Tilted]

I suspect you have erred in what you didn't show us. Anyway, what do think happens if you let n=1?

5$\pi$/2=5$\pi$/2

 

[PAllen]

5$\pi$/2=5$\pi$\2

not with what you wrote in the initial post. Hard to help till you fix the OP.

 

[gb7nash]

This statement is false. To reiterate what others have said, look at your previous work leading up to this point and try to find out where you made the error.

 

[Tilted]

Ah I found the problem.

I figured it out, thanks for your help.

 

[Mark44]

(n+$\pi$/2)+n$\pi$=(2n+1/2)$\pi$

n=0,1,2,3...

I suspect you have erred in what you didn't show us. Anyway, what do think happens if you let n=1?

5$\pi$/2=5$\pi$/2

Based on your first post, I don't see how you can get 5π/2 on the left side, when n = 1.

To get 5π/2 on the left side, you would have to have (π + π/2) + π, but you have N + π + π/2. When N = 1, this is equal to 1 + π/3 (I'm using N because π ("pi") and n look almost the same).

 

[Tilted]

Based on your first post, I don't see how you can get 5π/2 on the left side, when n = 1.

To get 5π/2 on the left side, you would have to have (π + π/2) + π, but you have N + π + π/2. When N = 1, this is equal to 1 + π/3 (I'm using N because π ("pi") and n look almost the same).

I used the equation on my paper. ( I put the wrong one on the OP by accident )

Correct Equation is:

(n$\Pi$+$\Pi$/2)+n$\Pi$=(2n+1/2)$\Pi$

Which can be shown to be equal with some algebra.

2n$\Pi$+$\Pi$/2=2n$\Pi$+$\Pi$/2

Sorry for forgeting the pi in the OP :(.