Prove or Disprove: (n\Pi+\Pi/2)+n\Pi=(2n+1/2)\Pi

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Homework Help Overview

The discussion revolves around proving or disproving the equation (n + π/2) + nπ = (2n + 1/2)π for non-negative integers n. Participants are examining the validity of the equation and exploring specific values of n.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the original poster's simplifications and calculations, particularly when substituting n = 1. There is a focus on verifying the correctness of the equation and identifying potential errors in the initial setup.

Discussion Status

Some participants have pointed out inconsistencies in the original post and have encouraged the poster to review their previous work. There is an acknowledgment of a possible error, and one participant claims to have resolved their confusion, although the overall consensus on the equation's validity remains unclear.

Contextual Notes

There is mention of a correction to the equation provided by the original poster, indicating that the initial equation may have been misstated. This correction is significant to the ongoing discussion.

Tilted
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Homework Statement


Prove or disprove the following equation.

(n+\pi/2)+n\pi=(2n+1/2)\pi

n=0,1,2,3...

Homework Equations


None.


The Attempt at a Solution


I have simplified the equation to this form, I just need help proving it.

Thanks in advance.
 
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I suspect you have erred in what you didn't show us. Anyway, what do think happens if you let n=1?
 
PAllen said:
I suspect you have erred in what you didn't show us. Anyway, what do think happens if you let n=1?

5\pi/2=5\pi/2
 
Tilted said:
5\pi/2=5\pi\2

not with what you wrote in the initial post. Hard to help till you fix the OP.
 
This statement is false. To reiterate what others have said, look at your previous work leading up to this point and try to find out where you made the error.
 
Ah I found the problem.

I figured it out, thanks for your help.
 
Tilted said:
(n+\pi/2)+n\pi=(2n+1/2)\pi

n=0,1,2,3...

PAllen said:
I suspect you have erred in what you didn't show us. Anyway, what do think happens if you let n=1?

Tilted said:
5\pi/2=5\pi/2
Based on your first post, I don't see how you can get 5π/2 on the left side, when n = 1.

To get 5π/2 on the left side, you would have to have (π + π/2) + π, but you have N + π + π/2. When N = 1, this is equal to 1 + π/3 (I'm using N because π ("pi") and n look almost the same).
 
Mark44 said:
Based on your first post, I don't see how you can get 5π/2 on the left side, when n = 1.

To get 5π/2 on the left side, you would have to have (π + π/2) + π, but you have N + π + π/2. When N = 1, this is equal to 1 + π/3 (I'm using N because π ("pi") and n look almost the same).

I used the equation on my paper. ( I put the wrong one on the OP by accident )

Correct Equation is:

(n\Pi+\Pi/2)+n\Pi=(2n+1/2)\Pi

Which can be shown to be equal with some algebra.

2n\Pi+\Pi/2=2n\Pi+\Pi/2

Sorry for forgeting the pi in the OP :(.
 

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