Prove that (1+tanx)^2-2tanx=1/(1-sinx)(1+sinx)

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SUMMARY

The equation (1+tanx)^2 - 2tanx = 1/(1-sinx)(1+sinx) can be proven by manipulating both sides. The left side simplifies to 1 + tanx^2, which is equivalent to secx^2, confirming the identity. The right side simplifies to 1/(1-sinx)(1+sinx) = 1/cos^2x, thus establishing that secx^2 = 1/cos^2x. This proof validates the relationship between tangent and secant functions in trigonometric identities.

PREREQUISITES
  • Understanding of trigonometric identities, specifically tangent and secant functions.
  • Familiarity with algebraic manipulation of equations.
  • Knowledge of the Pythagorean identity: sin^2x + cos^2x = 1.
  • Basic calculus concepts, particularly limits and continuity, may be beneficial.
NEXT STEPS
  • Study the derivation of trigonometric identities, focusing on tangent and secant functions.
  • Learn about the Pythagorean identities and their applications in trigonometry.
  • Explore the relationship between sine, cosine, and their respective secant and cosecant functions.
  • Practice solving trigonometric equations using algebraic techniques and identities.
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Students studying trigonometry, mathematics educators, and anyone looking to deepen their understanding of trigonometric identities and their proofs.

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Homework Statement


prove that: (1+tanx)^2-2tanx=1/(1-sinx)(1+sinx)

Homework Equations


Main question is does 1/cosx^2 = secx^2? More in my attempt at the solution.

The Attempt at a Solution


(1+tanx)^2-2tanx=1/(1-sinx)(1+sinx)

(1+tanx)(1+tanx)= 1+2tanx+tanx^2
1+2tanx+tanx^2-2tanx=1+tanx^2
1+tanx^2=secx^2

Now to the right side.

1/(1-sinx)(1+sinx)= 1/1-sinx^2 Now i will solve for the denominator.
1-sinx^2=cosx^2 the equation is now:

1/cosx^2. I know that secx=1/cosx my main question is does secx^2=1/cosx^2? This would give me my correct answer but I somehow feel that if you square secx it does not = 1/cosx.
 
Physics news on Phys.org
If
[tex]\frac{1}{\cos x}= \sec x[/tex]
then certainly
[tex]\frac{1}{\cos^2 x}= \sec^2 x[/tex]
.
 

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