- #1

Schaus

- 118

- 5

## Homework Statement

(secx+1)/(sin2x) = (tanx)/2cosx-2cos

^{2}x)

## Homework Equations

## The Attempt at a Solution

Left Side

((1+cosx)/cosx)/2sinxcosx

((1+cosx)/cosx) x (1/2sinxcosx)

cancel the a cosx from both to get

(1/2sinxcosx)

This is all I could manage with left side so I tried right side

Right Side

(sinx/cosx)/2cosx-2cos

^{2}x)

I'm stuck here. I've been trying to find something to change the denominator of the Right Side but I can't think of anything that will work. If someone could let me know where I am going wrong it would be greatly appreciated!