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suppose that x and y are real numbers. Prove that if x≠0 then if y= 3x^2+2y/x^2+2 then y=3

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- Thread starter bean29
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- #1

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suppose that x and y are real numbers. Prove that if x≠0 then if y= 3x^2+2y/x^2+2 then y=3

- #2

mathman

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y(1-2/x^{2}) = 3x^{2} + 2

y = (3x^{4} + 2x^{2})/(x^{2}-2)

Doesn't look constant.

y = (3x

Doesn't look constant.

- #3

rubi

Science Advisor

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[tex]y = \frac{3x^2+2y}{x^2+2}[/tex].

Then it works out:

[tex]y x^2 + 2y = 3x^2 + 2y \Leftrightarrow y x^2 = 3 x^2 \Leftrightarrow y = 3[/tex]

- #4

mfb

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