acen_gr said:
This is my work. Is this right?
Every step is mathematically equivalent to its preceding step (so you haven't broken any rules) so yes, it's right
If I'm to be a bit picky however, I'll mention that it's not necessary to write ... = RHS on every line. You should instead set out your proof as so:
LHS = ...
= ...
= ...
= RHS
You don't need to keep writing LHS either, unless you make any manipulations to both sides of the equality such as:
LHS = ...
LHS + 1 = ... + 1
Although you shouldn't do this when trying to prove LHS = RHS. If you needed to add 1 to the RHS then you can minus one to keep it balanced as so:
LHS = ...
= ... + 1 - 1
acen_gr said:
1 - 3cos2x + 3(cos2x)(cos2x) = RHS
I'd also skip this line altogether (unless it's to help you to personally keep track of things and not get confused), but if not, you should just go ahead and factorize straight away:
[tex]=1-3\cos^2x+3cos^4x[/tex]
[tex]=1-3\cos^2x(1-cos^2x)[/tex]
acen_gr said:
1 - 3cos2x(sin2x) = RHS
1 - 3cos2xsin2x = 1 - 3sin2xcos2x
Also this last line is unnecessary, but there's no harm done if you feel like doing it.