Why Does cos(180-Θ) = -cos(Θ)?

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Homework Help Overview

The discussion revolves around understanding the trigonometric identity cos(180-Θ) = -cos(Θ) using the unit circle. Participants are exploring the geometric interpretation of cosine in relation to angles and their positions on the unit circle.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to approach the problem and questions the relevance of the unit circle to the identity. Some participants suggest visualizing the unit circle and considering the definition of cosine as the x-coordinate. Others mention using addition formulas and reflect on the properties of angles in different quadrants.

Discussion Status

Participants are actively engaging with the problem, offering various insights and methods of visualization. There is a mix of suggestions, including drawing the unit circle and considering the properties of angles in different quadrants, but no consensus has been reached yet.

Contextual Notes

Some participants note the importance of understanding the quadrant in which the angle 180-Θ lies, specifically mentioning that it falls in the second quadrant where cosine is negative. The original poster's lack of familiarity with the topic is also acknowledged.

teetar
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1. Explain, using a unit circle diagram, why cos(180-Θ) = -cos(Θ)

2. My Attempt at a Solution:
I have no idea how to begin thinking of this. I don't know any of the obvious details of the question, the only rational thought I can currently form is that cos(Θ) = the x-coordinate of the terminal angle's intersection with a unit circle, however, I don't even know if that's related to the question. I cannot form any simple thoughts regarding this question. I have no idea where to begin, so I'm just wondering if someone here might be able to say something that could point me in the correct direction of an answer. Thanks!
 
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Draw a circle... Think about how you can indicate cosine on the circle. You already know the definition of cosine, so you are on the right track...
 
Or if you have had the addition formulas you can use the formula for ##\cos(a-b)##.
 
LCKurtz said:
Or if you have had the addition formulas you can use the formula for ##\cos(a-b)##.

The question asked to explain using a unit circle diagram.
 
If you look at the unit circle, you can notice that the x-values are "reflective" of each other in the top half. This is because at the 90\deg point, x=0 so when you decrease the angle, x increases the same amount as it would decrease if you had rather increased the angle. From this observation, you can make the statements that \cos(90-\theta)=x and \cos(90+\theta)=-x Now, do what you will with those statements and the relation \cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b)
 
Here's an image I made (sorry for the bad quality) that will show you the intuition behind that formula:
ywwru.png

$$\color{#50F}{\cos(\pi-\theta)}=-\color{fuchsia}{\cos(\theta)}.$$
 
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"unit circle" means its radius is 1. So sine = opp/hyp = opp/1 = opp
 
What you have to remember is that when you draw your unit circle, you need to remember ASTC.

The region which 180-θ falls in is the second quadrant — or, the S quadrant. In this quadrant, only sin is positive. So cos(180-θ)=-cosθ

Hope this helps ~| FilupSmith |~
 

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