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Prove that spin in arbitary direction is hbar/2

  1. Oct 17, 2007 #1

    cks

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    the question is in the jpeg file.
     

    Attached Files:

  2. jcsd
  3. Oct 17, 2007 #2
    How come you don't just solve the eigenvalues for the matrix that you have denoted by [tex]S_{z'}[/tex]? We are not interested in the eigenvalues of [tex]S_{z'}^2[/tex], but just on the eigenvalues of the spin matrix you have constructed in the fourth line of your attachment. I think you have got a bit messed up with the eigenvalues related to the total spin angular momentum [tex]S^2=S_x^2+S_y^2+S_z^2[/tex] and the component of spin angular momentum related to an arbitrary direction.

    I hope this made any sense to you, it's my first post!
     
    Last edited: Oct 17, 2007
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