Prove that tangents to the focal cord of parabola....

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Discussion Overview

The discussion revolves around proving that the tangents to any focal chord of a parabola are perpendicular, utilizing the reflection property of parabolas. Participants explore geometric reasoning and reflection principles related to the tangents and focal chords.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests using the reflection property of parabolas to prove the tangents to the focal chord are perpendicular, expressing uncertainty about the solvability of the problem with the provided details.
  • Another participant describes a geometric approach involving rays reflecting off the focal chord and discusses the angles of incidence and reflection, questioning the relationship between these angles and the tangents.
  • A similar geometric explanation is reiterated, emphasizing the angles involved and the complexity of the geometry.
  • Participants discuss the angles of the tangents at points of reflection for rays descending at different abscissas, noting that one tangent has an angle of 45 degrees and the other -45 degrees, leading to a conclusion about their perpendicularity.
  • One participant clarifies that the original question pertains to proving that any focal chord through the focus has perpendicular tangents, not just the latus rectum, and expresses a desire to use the reflection method rather than analytical geometry.
  • Another participant points out the distinction made by the original poster regarding "the" focal chord versus "any" focal chord, suggesting that the argument can be adjusted to apply to any focal chord by considering rays reflecting at either end of the chord.
  • A participant acknowledges the simplicity of the triangle formed by the focal chord and tangents, appreciating the insight provided by another participant.

Areas of Agreement / Disagreement

Participants exhibit some disagreement regarding the interpretation of the original question, specifically whether it pertains to "the" focal chord or "any" focal chord. However, there is a general agreement on the geometric principles involved in the reflection and the angles of the tangents.

Contextual Notes

Some participants express uncertainty about the geometry involved and the specific assumptions regarding the angles and reflections. The discussion does not resolve these uncertainties, leaving the geometric relationships somewhat tangled.

Vriska
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Prove that tangents to the focal cord of parabola are perpendicular using the reflection property of parabola ( A ray of light striking parallel to the focal plane goes through the focus, and a ray of light going through the focus goes parallel)

I don't know whether this is solvable with just this much detail, just something I've been thinking about, looks doable but I've not been able to get anywhere. The geometry is quite tangled.
 
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The geometry is reasonably simple as long as one approaches it from the correct perspective.

Consider a parabola in the number plane whose axis of symmetry is the y-axis and the apex is the origin. Now consider two rays that travel vertically down and are reflected along the focal chord, which is horizontal. One of the rays descends at abscissa ##a## and the other at abscissa ##-a##, where the value of ##a## depends on the shape of the parabola.

Consider the ray that comes down at abscissa ##a##. What is the angle between its incident ray and its reflection? What does that enable us to say about the angle between the focal chord (along which the reflected ray travels) and the tangent to the parabola at the point of reflection?
 
andrewkirk said:
The geometry is reasonably simple as long as one approaches it from the correct perspective.

Consider a parabola in the number plane whose axis of symmetry is the y-axis and the apex is the origin. Now consider two rays that travel vertically down and are reflected along the focal chord, which is horizontal. One of the rays descends at abscissa ##a## and the other at abscissa ##-a##, where the value of ##a## depends on the shape of the parabola.

Consider the ray that comes down at abscissa ##a##. What is the angle between its incident ray and its reflection? What does that enable us to say about the angle between the focal chord (along which the reflected ray travels) and the tangent to the parabola at the point of reflection?

The angle between the reflected and incident is 90 - the angle of the tangent wrt the perpendicular is 45. I'm not sure what to do after this, I'm still finding the geometry tangled
 
OK, now what about the tangent at the point of reflection of the ray that comes down at abscissa ##-a##.

What can we then say about the angle between that and the other tangent?
 
andrewkirk said:
OK, now what about the tangent at the point of reflection of the ray that comes down at abscissa ##-a##.

What can we then say about the angle between that and the other tangent?

One is 45 the other is - 45. Angle between them is 90
 
You're welcome.
 
andrewkirk said:
You're welcome.
? noo , not this, the question was to prove *any* focal chord through the focus (not only latus rectum) has tangents that are perpendicular. I can do it with analytical geometry, but i want to do it with the reflection thing.
 
The OP said *the*, not *any*.

But in any case, the argument needs only minor adjuistment to apply it to any focal chord. Just consider the two rays heading parallel to the parabola axis after reflection at either end of a given focal chord. Label the angle of incidence for one of those rays ##a## and that for the other as ##b##. Using rules of reflection and completing the triangle formed by the focal chord and the two tangents we see that the angle between the tangents is right.
 
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andrewkirk said:
The OP said *the*, not *any*.

But in any case, the argument needs only minor adjuistment to apply it to any focal chord. Just consider the two rays heading parallel to the parabola axis after reflection at either end of a given focal chord. Label the angle of incidence for one of those rays ##a## and that for the other as ##b##. Using rules of reflection and completing the triangle formed by the focal chord and the two tangents we see that the angle between the tangents is right.

Ah thank you so much, the triangle thing was brilliant - and simple.
 

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