Prove that the components of a vector can be written as follows

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The discussion centers on the representation of vector components using the notation [a,b,c] = a ^ b . c, which refers to the scalar triple product in three-dimensional space. Participants explore the implications of this notation, clarifying that the '^' symbol denotes the cross product, while the expression represents the dot product of the resulting vector with another vector. The conversation also touches on the basis formed by the standard unit vectors {e_1, e_2, e_3}, emphasizing the unique representation of vectors in this basis. The clarification of terms, such as distinguishing between the scalar and vector triple products, is a key point of the discussion. Overall, the thread highlights the geometric and algebraic approaches to understanding vector components and their relationships.
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Homework Statement
All below, well
Relevant Equations
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1592759390018.png

That is, the triad forms a basis.
 
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[a,b,c] = a ^ b . c

I thought that i could begin with a matrix, immediately i see the problem seeing by this way, so "never mind". I don't know how the properties would help me here, i think i will need to evaluate by geometry approach, but i am not sure.
 
Since ##\{e_1,e_2,e_3\}## is a basis, you can uniquely write ##x=a_1e_1+a_2e_2+a_3e_3.## To solve for ##a_1##, for example, try crossing both sides with ##e_2## and then dotting both sides by ##e_3.##
 
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LCSphysicist said:
[a,b,c] = a ^ b . c
What does this notation mean, particularly '^'?
 
I assumed cross/exterior product (the latter is more general, but in ##\mathbb{R}^3## is basically equivalent). The latex would be "##\wedge##".
 
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So does the notation ##[\vec{a}, \vec{b}, \vec{c}]## mean the vector triple product (in ##\mathbb{R}^3##)?
 
It means the scalar triple product, ##[a,b,c]=(a\times b)\cdot c.##
 
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Infrared said:
It means the scalar triple product, ##[a,b,c]=(a\times b)\cdot c.##

Whoops, yes that's the one I was thinking of. Apparently what's called the vector triple product is something else. Makes sense, thanks!
 

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