For all $x > 0$, $$(x^2 + x)^2 = x^4 + 2x^3 + x^2 < x^4 + 2x^3 + 2x^2 + 2x + 1 < x^4 + 2x^3 + 3x^2 + 2x + 1 = (x^2 + x + 1)^2$$ As $y$ is sitting in between two consecutive perfect squares for $x \in \Bbb N \setminus \{0\}$, $y$ cannot itself be a perfect square.
#3
kaliprasad
Gold Member
MHB
1,333
0
$y=x^4+2x^3+2x^2+2x+1$
=$x^4+2x^2+1+2x^3+2x$
=$(x^2+1)^2+2x(x^2+1)$
= $(x^2+1)(x^2+2x+1)$
= $(x^2+1)(x+1)^2$
as $x^2+1$ is between $x^2$ and $(x+1)^2$ and not a perfect square and $(x+1)^2$ is so the product is not a perfect square
Here is a little puzzle from the book 100 Geometric Games by
Pierre Berloquin.
The side of a small square is one meter long and the side of
a larger square one and a half meters long. One vertex of the
large square is at the center of the small square. The side of
the large square cuts two sides of the small square into one-
third parts and two-thirds parts.
What is the area where the squares overlap?