Is this theory regarding the graph and the square root valid?

In summary, the conversation is about the use of a graph to find the value of $\sqrt3$. The method involves substituting $\sqrt3$ for $x$ in a given quadratic equation and observing the results. The conversation also discusses the validity of this method for finding the square root of any number.
  • #1
mathlearn
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http://mathhelpboards.com/pre-algebra-algebra-2/find-value-squareroot-3-using-graph-drawing-suitable-straight-line-19973.html

greg1313 said:
Mathematics is a science and experimentation is a valuable tool. The first thing I did was to substitute $\sqrt3$ for $x$ in the given quadratic and observe the results. Get your hands dirty!
I guess I found a method to obtain the square root of any number using the above graph.

$x^2-2x-3$ What I did to find the square root of 3 was replace $x^2$ with the desired square root

$\sqrt{3}^2-2x-3=3-2x-3=-2x=0=y$

And check this out if we replace the $x^2$ of the formula of the formula to obtain a square root of any number

$\sqrt{7}^2-2x-3=7-2x-3=-2x+4=0=y$

Check the $x$ axis of the intersection point of the graph and the x axis

Is this theory regarding the graph and the square root really valid?

[graph]z0awzx3ity[/graph]
 
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  • #2
Re: An amazing discovery regarding the graph and the square root

mathlearn said:
$\sqrt{3}^2-2x-3=3-2x-3=-2x=0=y$
If \(\displaystyle x = \sqrt{3}\) then \(\displaystyle x^2 - 2x - 3 = (\sqrt{3})^2 - 2 \sqrt{3} - 3\). You have to replace all the x's.

Also: \(\displaystyle \sqrt{3}^2-2x-3=3-2x-3=-2x=0\) says that -2x = 0, but you originally had \(\displaystyle x = \sqrt{3}\), which both can't be true.

-Dan
 

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