Ok. To do mathematical induction, I was taught to do this in 3 steps. These 3 steps are:
1) Show true for n = 1
2) Assume true for n=k.
By doing this assumption, you set up for the third step by proving true for n=k+1, which will prove that n = k is also true.
3) Prove true for n = k+1.
Follow these steps throughout and see how it goes from there. I'll give you a little head start but try to finish it off.
Step 1: Show true for n=1
[tex]1^3+2(1) = 3[/tex] (which is divisable by 3)
Step 2: Assume true for n = k
i.e. Assume [tex]3 | k^3+2(k)[/tex] (induction hypothesis)
Step 3: Prove true for n = k+1
i.e. Prove that [tex]3 | (k+1)^3+2(K+1)[/tex]
Expand out [tex](k+1)^3+2(k+1)[/tex] and when you fully simplify it out, try to keep your induction hypothesis ([tex]k^3+2(k)[/tex]) separate and see what's left over in your simplified expression. It should result in something that is divisible by 3. Show us how you expand it out and if you make any errors, we'll help you out gladly. But if you don't do the work, we won't help you. It's as simple as that. Effort needs to be shown, not just a problem that's shoved in our faces.