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Sumedh
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Prove that n^n (is less than or equal to) 1*3*5...(2n-1).Where n is any natural no.
Prove that n^n (is less than or equal to) 1*3*5...(2n-1)
n^n ≥ 1*3*5...(2n-1)
.Where n is any natural number.I think Arithmetic or Geometric progression is used (A.P.>G.P.)
i don't know how to solve this type of questions.
please give hints only for how to solve
Homework Statement
Prove that n^n (is less than or equal to) 1*3*5...(2n-1)
n^n ≥ 1*3*5...(2n-1)
.Where n is any natural number.I think Arithmetic or Geometric progression is used (A.P.>G.P.)
The Attempt at a Solution
i don't know how to solve this type of questions.
please give hints only for how to solve