Proving (a+b+c)^3=a^3+b^3+c^3 Leads to (a+b+c)^5=a^5+b^5+c^5

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Homework Help Overview

The discussion revolves around proving the algebraic identity that states if \((a+b+c)^3 = a^3 + b^3 + c^3\), then it leads to \((a+b+c)^5 = a^5 + b^5 + c^5\). The subject area is algebra, specifically focusing on polynomial identities and their implications.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss numerical verification as a preliminary step, questioning whether this approach can serve as a valid proof. There is also a call for the original poster to share any attempts made towards the proof.

Discussion Status

The discussion is ongoing, with some participants suggesting numerical examples to illustrate the identities, while others emphasize the need for a formal proof. There is no explicit consensus on the approach to take yet.

Contextual Notes

Participants note that numerical verification does not constitute a proof, highlighting the need for a more rigorous approach. There is an implicit understanding that the original poster may need to clarify their attempts or reasoning further.

ashrafmod
show that
(a+b+c)^3=a^3+b^3+c^3
implies that
(a+b+c)^5=a^5+b^5+c^5
 
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What have you tried to do?
 
Moved to homework forum.
 
The first step you could do is put in numbers and verify it works numerically =).

Let's say

x * y^2 = x * y * y
x = 3, y = 2

3 * 2^2 = 12. (3 * 4 = 12)
3 * 2 * 2.

3 * 2 * 2 = 3 * 4 = 12
3 * 2 = 6 -> 6 * 2 = 12.

Thus, they are the same since they end up with the same answer =).
 
Last edited:
AngeloG said:
The first step you could do is put in numbers and verify it works numerically =).

Let's say

x * y^2 = x * y * y
x = 3, y = 2

3 * 2^2 = 12. (3 * 4 = 12)
3 * 2 * 2.

3 * 2 * 2 = 3 * 4 = 12
3 * 2 = 6 -> 6 * 2 = 12.

Thus, they are the same since they end up with the same answer =).

But that's not a proof; that's just showing it for certain numbers.

ashrafmod: have you tried anything?
 

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