Proving Bounded Open Sets Union of Disjoint Open Intervals

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    Bounded Sets
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Discussion Overview

The discussion revolves around the proof that any bounded open subset of the real numbers (R) can be expressed as the union of disjoint open intervals. Participants explore the implications of this statement and clarify their understanding of what constitutes a disjoint union of open intervals.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant expresses confusion about how a bounded open set, specifically an open interval (a,b), can be represented as a union of disjoint open intervals, suggesting that there will always be points in the interval not included in the union.
  • Another participant proposes splitting the interval (a,b) into two parts, (a, (a+b)/2) and ((a+b)/2, b), but questions the inclusion of the midpoint (a+b)/2.
  • A third participant suggests that perhaps the union of the open interval with an empty set could be considered, though they are uncertain if this aligns with the intended proof.
  • One participant clarifies that the term "disjoint union of open intervals" can include a single open interval, asserting that (a,b) itself qualifies as a union of one open set, and emphasizes that the theorem primarily addresses open sets that are not intervals.
  • A later reply acknowledges the clarification, indicating that it has helped to clear up their understanding.

Areas of Agreement / Disagreement

Participants exhibit some disagreement regarding the interpretation of the term "disjoint union of open intervals." While there is clarification on the definition, the initial confusion about the proof remains unresolved.

Contextual Notes

The discussion reflects varying interpretations of the theorem and the nature of open sets, highlighting the need for precise definitions and understanding of concepts related to unions of intervals.

Gear300
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I am asked to prove that any bounded open subset of R is the union of disjoint open intervals.
If S = open interval (a,b), I don't really see how this could be the case (there will always be points in S that are not in the union of the disjoint sets).
 
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The first thing that comes to mind is [tex]\left(a, \frac{a+b}{2} \right) \cup \left( \frac{a+b}{2}, b \right)[/tex], but like you said, what about [tex]\frac{a+b}{2}[/tex]?
 
TylerH said:
The first thing that comes to mind is [tex]\left(a, \frac{a+b}{2} \right) \cup \left( \frac{a+b}{2}, b \right)[/tex], but like you said, what about [tex]\frac{a+b}{2}[/tex]?

I don't know. Perhaps its a trivial instance in this case: S U {}, a union with a null set, in which the null set is both open and closed. Though, I'm not sure if this is what they have in mind.
 
You are interpreting the phrase "disjoint union of open intervals" incorrectly. The union may be of any number of open intervals including 1. The example you are asking about, (a, b), is an open interval and so is the union of 1 open set- itself.

The "meat" of the theorem is that open sets that are NOT intervals can be written as unions of open intervals.
 
HallsofIvy said:
You are interpreting the phrase "disjoint union of open intervals" incorrectly. The union may be of any number of open intervals including 1. The example you are asking about, (a, b), is an open interval and so is the union of 1 open set- itself.

The "meat" of the theorem is that open sets that are NOT intervals can be written as unions of open intervals.

That makes things more clear. Thanks.
 

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