Proving differentiability of function on a Lie group.

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SUMMARY

The discussion centers on proving the differentiability of the function \( f: G \rightarrow G; x \mapsto x^{-1} \) for a Lie group \( G \), as outlined in Choquet-Bruhat's "Analysis, Manifolds, and Physics." The key insight is that the differentiability can be established using the definition of a Lie group, specifically by demonstrating that the map \( G \times G \rightarrow G; (x, y) \mapsto xy^{-1} \) is differentiable. By setting \( x = e \), the identity element, the proof simplifies significantly. Participants also discussed formatting issues with inline LaTeX.

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  • Familiarity with differentiability in the context of manifolds
  • Knowledge of charts and transition maps in differential geometry
  • Basic proficiency in LaTeX for mathematical notation
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On page 116 of Choquet-Bruhat, Analysis, Manifolds, and Physics, Lie groups are defined, and the first exercise after that asks you to prove that
for a Lie group G

<br /> f:G \rightarrow G; x \mapsto x^{-1}<br />

is differentiable. I know from the previous definitions that a function f on a manifold is differentiable at x if

<br /> \psi \circ f \circ \phi^{-1}<br />

is differentiable, where (U, \phi) and (W, \psi) are charts for neighborhoods of x and y=f(x)=x^{-1}. It's probably an indication of how weak my analysis is, but I don't see how to proceed from there. Can anyone point me in the right direction?
 
Last edited:
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In the books which I have used your exercise is the definition of the Lie group :smile: ?.
 
Ah, OK, I see it now, you just prove it from the definition of a Lie group, which is that the map
from G \times G \rightarrow G; (x, y) \mapsto x y^{-1} is differentiable. Just let x = e, the identity element. I was making it way too difficult. BTW, does anyone know how to keep inline Latex from showing up above the line like that.
 
Last edited:

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