Proving Discontinuity of f(x,y) = xy / (x^2 + y^2) at (0,0)

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SUMMARY

The function f(x,y) = xy / (x² + y²) is proven to be discontinuous at the point (0,0) through the examination of limits along various paths. Specifically, evaluating the function along the line y = x yields a limit of 1/2, while along the line y = cx produces a limit of c/(1+c²), demonstrating that the limit depends on the path taken. This variability confirms the discontinuity at the origin. Additionally, the function f(x,y) = (x² + y) / √(x² + y²) also does not have a limit as (x,y) approaches (0,0), as shown by different results when approaching along the x-axis and y-axis.

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Homework Statement


Question 1. f(x,y) = xy / (x2+y2)
Show that f is discontinous at (0,0)

The Attempt at a Solution



if f(0,y) then f(x,y) = 0
if f(x,0) then f(x,0) = 0

If we consider other straight lines or parabola.
if y = x , if we choose y = cx
f(x,y) = x2 / x2+x2 = 1/2
f(x,y) = cx2 / x2+c2x2 = c/1+c2, and this can be any value depending on c

But how does this show that it is discontinuous specifically at 0?

Thanks!
 
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Another question, for f(x,y) = x2+y/ (x2+y2)1/2, Show that lim (x,y) -> (0,0) f(x,y) DNE

If i let f(x,0) we get x2/x = x
If i let f(0,y) we get y / y = 1

Is this a valid to show that the limit does not exisit if it approach from the x / y axis?
 

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