Proving Equivalency Relations: Help from Henry

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The discussion focuses on proving that the relation S defined on the set of real numbers, where x S y if x - y is an integer, is an equivalence relation. The user, Henry, successfully demonstrates that S is reflexive, symmetric, and transitive, thus confirming it as an equivalence relation. Additionally, Henry proves that S is a congruence relation with respect to addition by showing that if x S x' and y S y', then (x + y) S (x' + y'). This is established through the properties of integers involved in the definitions of S.

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henry1
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I'm having copious amounts of trouble with this question and an amount of help would really be appreciated.

Let S be the relation on the set of real numbers defined by

x S y iff x-y is an integer

1. prove that S is an equivalence relation on R.

2. Prove that if x S x' and y S y' then (x+y) S (x'+y').

Thanks,

Henry.
 
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Can you show what you have tried so far so our helpers can see where you are stuck or may be going astray?
 
My thoughts:

S is reflexive because 0 is an integer.

S is symmetric because -k is an integer whenever k is.

S is transitive, because the sum of two integers is another integer.

The second part of the problem is to show S is a congruence with respect to addition (of real numbers). This really just amounts to working through the definition of S:

Suppose x S x'. Then x - x' = k, for some integer k. Similarly, y S y' means y - y' = m, for some integer m.

Consequently:

(x + y) - (x' + y') = (x - x') + (y - y') = k + m, which is, of course, an integer.
 

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