Proving: \int\textbf{B}\cdot\textbf{H}d^{3}x=0

  • Thread starter Thread starter Old Guy
  • Start date Start date
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 2K views
Old Guy
Messages
101
Reaction score
1

Homework Statement


Prove [tex]\int\textbf{B}\cdot\textbf{H}d^{3}x=0[/tex]. There is no current density.



Homework Equations




The Attempt at a Solution

Through a vector identity and the divergence theorem, I get
[tex]\oint\Phi_{M}\textbf{B}\cdot{d}\textbf{a}[/tex] but don't know how to proceed. This seems close to Ampere's law with no enclosed current, but not quite.
 
Physics news on Phys.org
What surface are you integrating over? What are the values of [itex]\textbf{B}[/itex] and [itex]\Phi_M[/itex] along that surface?
 
He told us the problem was given to us intentionally very general, so none is specified. Could I argue that for an enclosed region in space with no enclosed magnetization, the integral is zero because all the flux in goes out again (kind of like the EM flux argument)?
 
Old Guy said:
He told us the problem was given to us intentionally very general, so none is specified. Could I argue that for an enclosed region in space with no enclosed magnetization, the integral is zero because all the flux in goes out again (kind of like the EM flux argument)?

No, I don't think that works...

[tex]\oint\Phi_{M}\textbf{B}\cdot{d}\textbf{a}[/tex]

does not represent the magnetic flux.

What is the exact wording on the original question? (If it's a problem from Jackson, just state the problem number)