Proving: limit (as theta approaches zero) of sin(theta)/(theta) = 1

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SUMMARY

The limit as h approaches zero of ((cosh - 1)/h) equals 0, as demonstrated through the transformation of the expression into -((2sin²(h/2))/h). This is further simplified using the identity cos(2x) = 1 - 2sin²(x), allowing the substitution of 2x with h. Ultimately, the limit evaluates to -1 multiplied by 0, confirming that the limit is indeed 0.

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Homework Statement


show that the limit as h approaches zero of ((cosh-1)/h) = 0.

Homework Equations



*The bold numbers preceding each line are simply line numbers, they are not apart of the equations.*

1 lim (as h approaches 0) of ((cosh - 1)/h)

2 = lim (as h approaches 0) of -((2sin2(h/2))/h)

3 = -lim as theta approaches zero of ((sin\Theta/\Theta)*sin\Theta

4 = -(1)(0)

5 = 0
I'm confused as to how the author of the text was able to get from line 1 to line 2. If someone could workout the steps between these two lines I would be appreciative. I'm drawing a blank here!

Thanks
 
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The author used this identity: cos(2x) = cos2(x) - sin2(x) = 1 - 2sin2(h), and then replaced 2x by h.
 
Ah, I see. Thank you.
 

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