Proving ∑mk=1k2=1/6(323+3m2+m) by Induction

moriheru · Mar 17, 2015

∑^m_k=1k²=1[/SUB]=1/6(32³+3m²+m)
How can I prove this by induction (m+1...)
Prove for example of m, substitute m+1 into the equation, find the sigma K² and solve the equation?

mathman · Mar 17, 2015

Two suggestions:
1. Move to math forum.
2. Proofread and correct equation.

http://en.wikipedia.org/wiki/List_of_mathematical_series#Sums_of_powers

Above contains correct expression.

moriheru · Mar 17, 2015

Sorry about the wrong forum.

Proving ∑mk=1k2=1/6(323+3m2+m) by Induction

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Proving ∑mk=1k2=1/6(323+3m2+m) by Induction

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