Proving Open and Closed Sets: A How-to Guide

  • Context: Graduate 
  • Thread starter Thread starter heyo12
  • Start date Start date
  • Tags Tags
    Closed Sets
Click For Summary
SUMMARY

This discussion focuses on proving the properties of open and closed sets in complex analysis, specifically the left half-plane defined as {z: Re z > 0} and the open disk D(z0, r). Participants emphasize the necessity of using the definition of open sets and the triangle inequality to establish these proofs. A key point raised is the relationship between closed sets and their complements, highlighting that if the complement of a set is open, then the original set is closed. The discussion also clarifies the definition of the closure of a disk, denoted as \overline{D(z0,r)}.

PREREQUISITES
  • Understanding of complex numbers and their properties
  • Familiarity with the definitions of open and closed sets in topology
  • Knowledge of the triangle inequality in metric spaces
  • Ability to work with set complements and limit points
NEXT STEPS
  • Study the definition and properties of open sets in topology
  • Learn how to apply the triangle inequality in proofs involving complex numbers
  • Research the concept of limit points and their significance in determining closed sets
  • Explore the relationship between a set and its closure in metric spaces
USEFUL FOR

Mathematics students, particularly those studying complex analysis or topology, as well as educators seeking to enhance their understanding of set properties in mathematical contexts.

heyo12
Messages
6
Reaction score
0
How can you prove sets
1---------
how can u prove the following sets are are open,
a. the left half place {z: Re z > 0 };
b. the open disk D(z0,r) for any [math]z_0 \varepsilon C[/math] and r > 0.

2---------
a. how can u prove the following set is a closed set:
_
D(z0, r)


MY WORKING SO FAR
1.. could you please give me a hint on how to start a and b as I've researched but still haven't got much of an idea. once i get a little hint then ill try solving and show you my working..

2a.
--------
if D(z0,r) is closed, this implies C\S (the compliment) is open. Therefore, for any z not belonging to the set, there is an e > 0 such that D(z,e) C C\S. This further implies z is not a limit point of S which means that it is a closed set?

is this correct proof for 2a??
 
Physics news on Phys.org
heyo12 said:
How can you prove sets
1---------
how can u prove the following sets are are open,
a. the left half place {z: Re z > 0 };
b. the open disk D(z0,r) for any z_0 \varepsilon C] and r > 0.
Use the definition of open set, of course. If the real part of z is negative, can you find a disk about z such that every point in it has real part negative? (b) is a little harder. Show that for any point p in D(z0,r) there exist a disk about p that is a subset of D(z0,r). You will need the triangle inequality.

2---------
a. how can u prove the following set is a closed set:
_
D(z0, r)


MY WORKING SO FAR
1.. could you please give me a hint on how to start a and b as I've researched but still haven't got much of an idea. once i get a little hint then ill try solving and show you my working..

2a.
--------
if D(z0,r) is closed, this implies C\S (the compliment) is open. Therefore, for any z not belonging to the set, there is an e > 0 such that D(z,e) C C\S. This further implies z is not a limit point of S which means that it is a closed set?

is this correct proof for 2a??
No, you certainly cannot start a proof That \overline{D(z0,r)} is closed by saying "if \overline{D(z0,r)} is closed"!
What, exactly, is your definition of \overline{D(z0,r)}?
 
well my definition of \overline{D}(z0,r)} was that it is a set which is a closed disk??

\overline{D(z0,r)} { w: |z0 - w | < r }
 

Similar threads

  • · Replies 22 ·
Replies
22
Views
4K
  • · Replies 12 ·
Replies
12
Views
6K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K