Proving Power Function for H0: p=1/2 in Coin Bias Test | X=8, 9, or 10

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SUMMARY

The discussion focuses on proving the power function for the hypothesis test H0: p=1/2 against H1: p>1/2 in a coin bias test, where p represents the probability of heads. The power function is derived as p^8(45-80p+36p^2) by calculating the probability of obtaining more than 7 heads (X=8, 9, or 10) in 10 tosses using the binomial distribution. Participants clarified that the power function is expressed for an arbitrary p, regardless of whether H0 is false. The key takeaway is the application of the binomial formula to derive the power function.

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A coin is suspected of bias towards heads, so a test is made of the hypothesis H0: p=1/2 against H1:p>1/2, where p is the probability of heads. The test is to count the number of heads, X, in 10 tosses of the coin, and reject H0 if X=8, 9, or 10.
Show that the power function for this test is given by: p^8(45-80p+36p^2)

I have no idea how to start. I know that the power function means: P(reject H0 given H0 is false) but i don't know how to continue.

Any help would be very much appreciated.
Thank you
 
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I think you can ignore the part "given H0 is false" because the test is expressed for an arbitrary p (which may or may not be the value of p under H1).

So, all you need is to express the probability of obtaining X > 7 in 10 throws using the binomial formula.
 
Oh right
Thank you v much!
(I should have known that)
 

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