Proving Projective Modules Have Free Modules as Direct Sums

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Discussion Overview

The discussion revolves around proving a property of projective modules, specifically that for a projective module P, there exists a free module F such that P + F is isomorphic to F. The scope includes theoretical aspects of module theory in algebra.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant requests assistance in proving that for a projective module P, there exists a free module F such that P + F = F.
  • Another participant questions the formulation of the original statement, suggesting that it is a standard result that a projective module P can be expressed as P + Q = F for some free module F and another module Q.
  • A third participant introduces the concept known as Eilenberg's trick, proposing that if Q is projective and F1 is free, then one can construct a free module F by taking a countable direct sum of F1, leading to the conclusion that P + F is isomorphic to F.
  • A later reply acknowledges the previous point and expresses familiarity with the concept, although not with its name.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the original claim regarding P + F = F, with some suggesting alternative formulations and approaches. The discussion includes competing views on the correct interpretation and proof structure.

Contextual Notes

There are unresolved assumptions regarding the definitions of projective and free modules, as well as the implications of the proposed constructions. The discussion does not clarify the necessary conditions for the existence of the modules involved.

Who May Find This Useful

Readers interested in module theory, particularly those studying projective and free modules in algebra, may find this discussion relevant.

peteryellow
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Please help me to prove that for a projective module P there exists a free module F, such that P +F =F.

Here + denotes direct sum = denotes isomorphic.

Thanks
 
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Did you really mean to write P + F = F? It's a standard result that a module is projective if and only if there is a module Q and free module F such that P + Q = F. Can you prove that?

It does seem to follow that there exists a free module F' with P + F' = F', although I've never seen it stated like that before.
 
I have seen this called Eilenberg's trick. The idea is that Q+P=F1 where Q is projective and F1 is free. Now let F=F1+F1+F1.. a countable number of times.

Then, P+F is isomorphic to P+Q+P+Q+P+Q.. which is isomorphic to F.
 
That's what I was thinking of, although I didn't know it was called Eilenberg's trick.
 

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