Proving the Brewster's angle formula tan θ = n₂/n₁

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unscientific
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Homework Statement



I have solved the first two parts, I'm having trouble with the final part.

Given the following relations, show the following relation of brewster angle:

[tex]tan θ = \frac {n_2}{n_1}[/tex]

Diagram of a light wave hitting a flat boundary, with n1 on the left and n2 on the right, showing incident wave A1, reflected wave A2, and transmitted wave A3 at angles θ1, θ2 and θ3 from the z axis, with the x axis vertical.


Homework Equations


The Attempt at a Solution



Using:

[tex]\frac {n_2}{n1} = \frac {sin θ_1}{sin θ_3}[/tex]

Starting from:

[tex]sin 2θ_3 = sin 2θ_1[/tex]
[tex]sin θ_3 cos θ_3 = sin θ_1 cos θ_1[/tex]
[tex]\frac {sin θ_1}{sin θ_3} = \frac {cos θ_3}{cos θ_1}[/tex]
[tex]\frac {n_2}{n_1} = \frac {\sqrt {1 - sin^{2}θ_3}}{cos θ_1}[/tex]
[tex]\frac {n_2}{n_1} = \sqrt { \frac {1}{sin^{2}θ_1} - ( \frac {n_1}{n_2} )^{2} } tan θ_1[/tex]

How do i show the square root term at the bottom = 1?
 
Last edited:
unscientific said:
Starting from:

[tex]sin 2θ_3 = sin 2θ_1[/tex]

Since ##\theta_1## and ##\theta_3## lie between 0 and ##\frac{\pi}{2}##, ##2\theta_1## and ##2\theta_3## lie between 0 and ##\pi##.

One way to solve ##\sin 2θ_3 = \sin 2θ_1## is to have ##\theta_1 = \theta_3##.

But there is also another relation between ##\theta_1## and ##\theta_3## that will satisfy ##\sin 2θ_3 = \sin 2θ_1##.
 
tsny said:
since ##\theta_1## and ##\theta_3## lie between 0 and ##\frac{\pi}{2}##, ##2\theta_1## and ##2\theta_3## lie between 0 and ##\pi##.

One way to solve ##\sin 2θ_3 = \sin 2θ_1## is to have ##\theta_1 = \theta_3##.

But there is also another relation between ##\theta_1## and ##\theta_3## that will satisfy ##\sin 2θ_3 = \sin 2θ_1##.

[tex]θ_1 = θ_3 + 2\pi[/tex]

Not sure if this helps at all..
 
unscientific said:
[tex]θ_1 = θ_3 + 2\pi[/tex]

Not sure if this helps at all..

We need to keep ##\theta_1## and ##\theta_3## less than ##\frac{\pi}{2}##, so ##2\theta_1## and ##2\theta_3## must lie between 0 and ##\pi##.

Sketch a graph of the sine function between 0 and ##\pi##. Draw a horizontal line that intersects the graph at two different angles. How are the two angles related?
 
TSny said:
We need to keep ##\theta_1## and ##\theta_3## less than ##\frac{\pi}{2}##, so ##2\theta_1## and ##2\theta_3## must lie between 0 and ##\pi##.

Sketch a graph of the sine function between 0 and ##\pi##. Draw a horizontal line that intersects the graph at two different angles. How are the two angles related?

[tex]θ_1 + θ_3 = \frac {\pi}{2}[/tex]
 
OK. Use this in Snell's law.
 
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TSny said:
OK. Use this in Snell's law.

Ha ha, the answer just pops right out!
 
unscientific said:
Ha ha, the answer just pops right out!

:bugeye:

Good.