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arctan(x) - arctan(x^3 +2x -((x^2 + 1)^(3/2)))

and

-arctan(x) + arctan(x^3 +2x + ((x^2 + 1)^(3/2)))

Any help would be greatly appreciated, I've been trying this for hours and I think I'm stuck in a rut.

Many Thanks!

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- Thread starter oxygengiver
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- #1

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arctan(x) - arctan(x^3 +2x -((x^2 + 1)^(3/2)))

and

-arctan(x) + arctan(x^3 +2x + ((x^2 + 1)^(3/2)))

Any help would be greatly appreciated, I've been trying this for hours and I think I'm stuck in a rut.

Many Thanks!

- #2

Ibix

Science Advisor

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- #3

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Thanks and we get tan of both are equal and we know both must be less than pi/2, problem solved!

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Prove that in any simple graph with more than two vertices, two equal paths of maximal length must intersect

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