Proving using rodrigue's formula (a very challenging question)

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SUMMARY

The discussion centers on proving the equation (n+1)Pn+1(x) - (2n+1)xPn(x) + nPn-1(x) = 0 using Rodriguez's formula. The participants highlight the challenges in differentiating the polynomial terms and emphasize the importance of correctly applying Rodriguez's formula to derive Pn+1 and Pn-1. Progress is being made by one participant who has discovered a method to differentiate (n+1) times, indicating a pathway to solving the problem.

PREREQUISITES
  • Understanding of Rodriguez's formula in polynomial theory
  • Familiarity with the properties of Legendre polynomials
  • Knowledge of differentiation techniques for polynomials
  • Basic grasp of recursive relationships in polynomial sequences
NEXT STEPS
  • Study the application of Rodriguez's formula to Legendre polynomials
  • Explore differentiation techniques for higher-order polynomials
  • Research the properties and recursive definitions of Pn(x)
  • Investigate examples of polynomial proofs using Rodriguez's formula
USEFUL FOR

Mathematicians, students studying advanced calculus, and anyone interested in polynomial theory and its applications in mathematical proofs.

artisticmath
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This is a very challenging question I would like your help guys to solve this question.
Prove (n+1)Pn+1(x)-(2n+1)xPn(x)+nPn-1(x)=0 using Rodriguez's formula
 
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What have you tried so far?
 
The problem is in differentiating ..I really find it very difficult to differentiate..
 
You still haven't said what you tried. Or are you saying that, because you are "find it very difficult to differentiate", you simply haven't tried at all?
 
I am making a progress .. I found a formula that allowed me to differentiate (n+1) times, so now am working on finding Pn+1 and Pn-1 by the Rodriguez formula , and then substituting them back in the equation..
 

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