Proving X=Y with Conditional Expectation

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SUMMARY

The discussion centers on proving that if two random variables X and Y satisfy the conditions \(\mathbb{E}(X|Y)=Y\) and \(\mathbb{E}(Y|X)=X\), then X equals Y almost surely (a.s.). Participants seek clarification on the definition of conditional expectation, \(\mathbb{E}(X|Y)\), to facilitate the proof. The consensus is that understanding the properties of conditional expectation is crucial for establishing the equality of the random variables.

PREREQUISITES
  • Understanding of random variables and their properties
  • Familiarity with conditional expectation, specifically \(\mathbb{E}(X|Y)\)
  • Knowledge of probability theory and measure theory
  • Basic skills in mathematical proof techniques
NEXT STEPS
  • Study the definition and properties of conditional expectation in probability theory
  • Explore the concept of almost sure convergence in measure theory
  • Review examples of proofs involving random variables and conditional expectations
  • Investigate the implications of the equality of random variables in probability
USEFUL FOR

Mathematicians, statisticians, and students of probability theory who are interested in advanced concepts of random variables and conditional expectations.

yavanna
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How can I do this?

Let X,Y r.v., [tex]\mathbb{E}(X|Y)=Y[/tex] and [tex]\mathbb{E}(Y|X)=X[/tex].
Proove that X=Y a.s.
 
Last edited:
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yavanna said:
How can I do this?

Let X,Y r.v., [tex]\mathbb{E}(X|Y)=Y[/tex] and [tex]\mathbb{E}(Y|X)=X[/tex].
Proove that X=Y a.s.

could you give the definition of [tex]\mathbb{E}(X|Y)[/tex] then it might be easier
 

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