Ptolemy's Theorem and Cyclic Quadrilateral

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Homework Statement


In cyclic quadrilateral ABCD with diagonals intersecting at E, we have AB=5, BC=10, BE=7, and CD=6. Find CE.

Homework Equations


Ptolemy's Theorem: The product of the measures of its diagonals is equal to the sum of the products of the measures of the pairs of opposite sides.

The Attempt at a Solution


I drew the picture and that's as far as I got.
 

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brisk11228 said:

Homework Statement


In cyclic quadrilateral ABCD with diagonals intersecting at E, we have AB=5, BC=10, BE=7, and CD=6. Find CE.

Homework Equations


Ptolemy's Theorem: The product of the measures of its diagonals is equal to the sum of the products of the measures of the pairs of opposite sides.

The Attempt at a Solution


I drew the picture and that's as far as I got.

Hint : First prove that ΔDEC is similar to ΔAEB by axiom AAA. To prove them similar , you have to apply theorem related to angles subtended by same segment or arc on circumference. Do you know what does that theorem state ?