Beverage engineering. The pull tab was a major advance in the engineering design of beverage containers. The tab pivots on a central bolt in the can's top. When you pull upward on one end of the tab, the other end presses downward on a portion of the can's top that has been scored. If you pull upward with a 10N force, approximately what is the magnitude of the force applied to the scored section? (You will need to examine a can with a pull tab.) After I measure the pull tab, I got: Pull tab length is 2.5cm From pulling zone to pivot is 1.75cm, let it = R and from pivot to pressing zone is 0.75, let it = r Given, pull upward 10N Can I calculate by using F1R = F2r 10 * 1.75 = 0.75 * F2 Fpressing = 23.33N Is this correct?