The controversial Cheviot open-pit coal mine in Alberta, Canada occupies 7,455 hectares (one hectare= 10^4 m^2) and produces 1.4 million tonnes of coal per year.
a) use the energy content of coal of 29 MJ/kg to find the power in watts corresponding to this rate of coal production., assuming it is burned with 35% efficiency.
b) using the assumption of 254 W/m^2 and 15% PV efficiency, find the area of a PV plant with the power output, and compare that number with the area of the Cheviot mine.
The Attempt at a Solution
For part A I did
1.4E9kg/yr * 1 yr/365 days * 1 day/24 hrs * 1 hr/3600 sec * 2.9E6 J/kg *.35 and got 450 MW
I have no idea how to start part B though