Pythagorean Theorem: Simplifying with Ab/Ab + Bc/Bc = Ac/Ac

[rudeonline]

Ab2 + Bc2 = Ac2

Can you also write this like..

Ab/Ab + Bc/Bc = Ac/Ac..?

 

[arildno]

What does your notation mean??

 

[rudeonline]

The question is of this notation is more our less the same.
If Ab2 and Bc2 have the same value...
Ab X Ab = Ab2 so Ab2/Ab =Ab

 

[matt grime]

err, no since presumably
Ab/Ab + Bc/Bc = Ac/Ac

is 1+1=1

 

[rudeonline]

0+0=0, mathematics don't lie...

 

[arildno]

..mathematics don't lie...

But a string of symbols is not necessarily mathematics..

 

[matt grime]

so Ab/Ab =0 does it...? oh...

 

[rudeonline]

Ab/Ab=1
AbxAb=Ab2
Ab2/Ab=Ab

Ab2/Ab + Bc2/Bc = Ac2/Ac

Example..

2x2/2 + 2x2/2 = Ac2/Ac...

 

[matt grime]

do you have a point (other than you don't seem to know any maths) or are you just trolling?

 

[rudeonline]

I try to proof that lightspeed should be zero.
If Ab ( time) and Bc ( distance ) are always the same for lightspeed.
Every second 300.000 km more, than is this not possible.
Only if time and distance are always the same, the speed of light is zero.
I think I can proof this with phytagoras.

If Ab2 + Bc2 = Ac2 you also coult write this down as
Ab/Ab + Bc/Bc = Ac/Ac.

This is only correct if the speed of light is zero. I think i have a good point here. It's hard to explain.

 

[Gza]

I'm not too sure of the notation you are using, so I couldn't really help you out. I think this post belongs in theory development from the looks of it.

 

[enigma]

Ab2/Ab + Bc2/Bc = Ac2/Ac

Uh... no...

a² + b² = c²

\frac{a^2}{c}+\frac{b^2}{c}=c

\frac{a}{c} + \frac{b^2}{c*a}=\frac{c}{a}

\frac{a}{c*b} + \frac{b}{c*a}=\frac{c}{a*b}

Seriously... you need to get through algebra before you go after general relativity.

 

[rudeonline]

I still don't have an answer if Ab2/Ab is the same as AbxAb.
And why Ab2 + Bc2 = Ac2 is not the same as Ab/Ab + Bc/Bc = Ac/Ac
I know that this formula only is correct if Ab and Bc are zero. But I think a got some point here.

 

[enigma]

I still don't have an answer if Ab2/Ab is the same as AbxAb.

Are you kidding? I just did it step by step for you.

A*A=A^2

A^2/A = A

A*A != A^2/A

And why Ab2 + Bc2 = Ac2 is not the same as Ab/Ab + Bc/Bc = Ac/Ac

See line by line derivation above.

But I think a got some point here.

DNFTT enigma...

 

[Zorodius]

I still don't have an answer if Ab2/Ab is the same as AbxAb.

Are you asking if "the product of a number and itself divided by that number" is equal to "the product of a number and itself"? No, unless that number is one.

The pythagorean theorem relates the lengths of the legs of a right triangle to the length of the hypotenuse. It doesn't say anything about the speed of light.

And why Ab2 + Bc2 = Ac2 is not the same as Ab/Ab + Bc/Bc = Ac/Ac
I know that this formula only is correct if Ab and Bc are zero. But I think a got some point here.

Since you're dividing by zero, it's not true then either.

Seriously... you need to get through algebra before you go after general relativity.

You're such a killjoy.

 

[humanino]

I try to proof that lightspeed should be zero.

Right, i could not get the point. Now I see...

 

[rudeonline]

err, no since presumably
Ab/Ab + Bc/Bc = Ac/Ac

is 1+1=1

Correct 1+1=1...

If you do 1 km + 1 sec you got 1 km/sec
Its correct that 1+1=2 but wat does 2 mean in this example...

 

[arildno]

Correct 1+1=1...

If you do 1 km + 1 sec you got 1 km/sec

splutter disgust

 

[Math Is Hard]

arildno, are you OK?? speak to me!
arildno..?

 

[Zorodius]

Correct 1+1=1...

Ah jeez, I memorized all those other numbers for nothing?

 

[rudeonline]

It's sad, how stupid people can be...
If you have 1 car with 4 persons, would you say 1 + 4 = 5 our...
1 + 4 = 4 persons/car...?

 

[arildno]

Thank you for your concern, Math is Hard, I thought I had pulled through, but then I didn't close my eyes fast enough to overlook rudeonline's last post..

 

[Integral]

It's sad, how stupid people can be...
If you have 1 car with 4 persons, would you say 1 + 4 = 5 our...
1 + 4 = 4 persons/car...?

I certainly would not, but isn't that what YOU are saying?

If you do 1 km + 1 sec you got 1 km/sec

Looks like we need to start with the basics for you. Notice that in the expression "1 km/sec" you use a "/" in grade school we are taught that this is a symbol of division, not addition. Why do you show addition on one side of the equal sign and division on the other? Are you familiar with the meaning of equality? Should not the same quantity be on both sides?

No I would not say 4 people + 1 car = 4 people/car but I would say that:
4 people/ 1 car = 4 people/car

or 4 people/ 2 car = 2 people/car

So now that you have had a lesson in grade school arithmetic perhaps you can take your ideas back to the drawing board and attempt to apply correct arithmetic to them.

 

[rudeonline]

Ab is a car
Bc is a person
Ac is persons per car.

1 person + 1 car = 1 person per car ( 1 P/c)

This is why Ab/Ab + Bc/Bc = Ac/Ac
1/1 + 1/1 = 1/1
car person = person/car

Now, if lightspeed is a constant one Ab en Bc are the same. Each second the distance is the same. If light would go faster our slower Ab our Bc would have a different value an be more as 1.

 

[Integral]

Did you bother reading my last post? Try again... If you cannot do simple arithmetic how can you hope to comprehend algebra, which is clearly beyond your skill set.

 

[rudeonline]

Wat is frong with my post?

 

[Chronos]

Er... How about misuse of arithmetric operators?

 

[rudeonline]

I try to explain that time and space are the same, nobody seems to want to see that. Not really a problem for me, just a pitty for scientists. But anyway, I will not be the first person witch was ignored till people became more clever.

 

[Alkatran]

I'm laughing pretty hard at this point.

According to you: 1+2 = 1/2
or: 3 = 0.5

Quick! Alert the media! Math is wrong! We have to get the word out...




Oh, and your obvious misuse of units should be pointed out. One second CAN'T BE EQUAL TO A METER. A meter is NOT time. That's like saying "I have enough weight here to power a small lamp!"

 

[rudeonline]

You've ever moved a meter wihout using time?