- #1

happyparticle

- 400

- 20

- TL;DR Summary
- How to linearized an equation to find the slope

Hi,

First of all, sorry if this is not the right place to post my question I was not sure where exactly to post this kind of question.

I'm wondering how can I find the value of a constant experimentally.

For instance, I have a equation ##l = AB^{4/3}##, with a set of data for ##I## and ##B##.

If the equation above was linear I could find the slope of the graph to get the value for ##A##.

However, this is not a linear equation.

I wondering if I have to linearize the equation and then find the slope to get the value for ##A##?

If so, how exactly I linearize it?

For instance an equation like ##A = BC^{2}e^{-D/C}## could be linearized by multiplying both side by ln, I think.

Thank you

First of all, sorry if this is not the right place to post my question I was not sure where exactly to post this kind of question.

I'm wondering how can I find the value of a constant experimentally.

For instance, I have a equation ##l = AB^{4/3}##, with a set of data for ##I## and ##B##.

If the equation above was linear I could find the slope of the graph to get the value for ##A##.

However, this is not a linear equation.

I wondering if I have to linearize the equation and then find the slope to get the value for ##A##?

If so, how exactly I linearize it?

For instance an equation like ##A = BC^{2}e^{-D/C}## could be linearized by multiplying both side by ln, I think.

Thank you