Pythagorean Theorem: Unexpected Finding

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SUMMARY

The discussion centers on an exploration of the Pythagorean Theorem, specifically examining the relationships between the squares of integers and their sums. The user discovered that when calculating combinations of squares up to 10, the square roots of the results exhibit a pattern of increasing odd numbers (3, 5, 7, 9, 11) that themselves increase by 2. This observation leads to a deeper inquiry into the differences between successive sums of squares, revealing a consistent pattern in the differences that aligns with the sequence of odd natural numbers.

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Angel11
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Hello, today i was playing around with the pythagorean theorem and found out something that i can't really explaing or atleast explain it with probably a false answer. So i was putting every possible combination with the max digit of 10. For example 1^2+1^2=\sqrt{2}, 1^2+2^2=\sqrt{5}... 10^2+1^2=\sqrt{101},10^2+2^2=\sqrt{104}. And then i found out that the square roots of the resolts are increasing by 3,5,7,9,11 and then i found out that those number are increasing by 2. so something like "1^2+2^2=\sqrt{(1^2+1^2)}+\sqrt{3} and then 1^2+3^2=\sqrt{(1^2+2^2)}+\sqrt{5}" so any idea how it works? my guess is WAY off i thought about it more and it is awful so i would appreciate anyones response.
 
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If I understand correctly, you have observed for example:

$$1^2+0^2=1$$

$$1^2+1^2=2$$

$$1^2+2^2=5$$

$$1^2+3^2=10$$

And you've seen that the difference between successive equations are the sequence of odd natural numbers. Let's look at the difference between two successive equations in general:

$$1^2+n^2=n^2+1$$

$$1^2+(n+1)^2=n^2+2n+2$$

What do we get when we subtract the former from the latter?
 

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