MHB Pythagorean Theorem: Unexpected Finding

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The discussion explores an unexpected pattern discovered while experimenting with the Pythagorean theorem using combinations of integers up to 10. The user noted that the square roots of the sums of squares exhibit an increasing sequence of differences: 3, 5, 7, 9, and 11, which themselves increase by 2. This observation leads to a deeper inquiry into the relationships between successive equations and their differences. Participants in the discussion analyze the mathematical implications of these findings, particularly focusing on the nature of the differences between successive sums of squares. The conversation emphasizes the intriguing connections within the Pythagorean theorem and invites further exploration of these patterns.
Angel11
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Hello, today i was playing around with the pythagorean theorem and found out something that i can't really explaing or atleast explain it with probably a false answer. So i was putting every possible combination with the max digit of 10. For example 1^2+1^2=\sqrt{2}, 1^2+2^2=\sqrt{5}... 10^2+1^2=\sqrt{101},10^2+2^2=\sqrt{104}. And then i found out that the square roots of the resolts are increasing by 3,5,7,9,11 and then i found out that those number are increasing by 2. so something like "1^2+2^2=\sqrt{(1^2+1^2)}+\sqrt{3} and then 1^2+3^2=\sqrt{(1^2+2^2)}+\sqrt{5}" so any idea how it works? my guess is WAY off i thought about it more and it is awful so i would appreciate anyones response.
 
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If I understand correctly, you have observed for example:

$$1^2+0^2=1$$

$$1^2+1^2=2$$

$$1^2+2^2=5$$

$$1^2+3^2=10$$

And you've seen that the difference between successive equations are the sequence of odd natural numbers. Let's look at the difference between two successive equations in general:

$$1^2+n^2=n^2+1$$

$$1^2+(n+1)^2=n^2+2n+2$$

What do we get when we subtract the former from the latter?
 

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