QCD Coulomb Singularity: Quarkonium w/ 2 Gluons

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    Coulomb Singularity
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mariamskhan
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Hi all,
I am just new to work on NLO in QCD. I need to know how a Coulomb singularity in QCD is defined? What is the form/expression of this singularity term? Can anyone explain with an example of any Feynman diagram? I am interested in the case of a quarkonium with two gluons in final state. I'll be really grateful for the help.
 
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Coulomb singularity appears whenever a virtual gluon is exchanged between quark pair of a meson. The limit that relative velocity of these two quarks tends to zero (to make a bound state for meson) in an expression ~ 1/v (v being realative velocity here) generates this singularity. This is what I know so far. I'm not sure where does this expression ~1/v come from? :cry: And with this information, I think we have Coulomb singularities only in QCD, but not in QED. :confused:
Can anybody please help or refer me to some good derivation of this? PLZZZZZZZZ
 
I do not know about which model you are talking. QCD, low-energy effective XYZ, non-relativistic quark model, ... I have never seen 1/v in full QCD.
 
Ooops, I really forgot to mention this. I'm talking about NRQCD.