Quantum, Spin, Orbital Angular momentum, operators

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The discussion focuses on deriving the matrix representation of the operator L·S for a particle with spin 1/2 and orbital angular momentum L, using two basis states. The participants are working on calculating the matrix elements <a|L·S|a>, <a|L·S|b>, <b|L·S|a>, and <b|L·S|b> by expanding L·S and applying the relevant operators to the basis vectors. There is confusion regarding the contraction of matrix terms and the effects of raising and lowering operators on the states. Clarifications are sought on how these operators interact with the defined states to facilitate the calculations. The conversation emphasizes the importance of understanding operator actions in quantum mechanics.
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Homework Statement



If a particle has spin 1/2 and is in a state with orbital angular momentum L, there are two basis states with total z-component of angular momentum m*hbar l L,s,Lz,sz > which can be expressed in terms of the individual states ( l L,s,Lz,sz > = l L,Lz > l s,sz > ) as

l a > = l L, 1/2 , m-1/2 , 1/2 > = l L, m-1/2 > l 1/2, 1/2 > = l L, m-1/2 > l alpha >
l b > = l L, 1/2 , m+1/2 , -1/2 > = l L, m+1/2 > l 1/2, -1/2 > = l L, m-1/2 > l beta >

Using these two states (l a > and l b >) as a basis, show that the matrix representation of the operator L.S is: where L.S = 1/2 ( L+S- + L-S+) + LzSz note all operators here with hats

L.S = Hbar ^2 /2 { (m-1/2) [ (L +1/2)^2 - m^2 ]^1/2

[ (L +1/2)^2 - m^2 ]^1/2 (m-1/2) }

Homework Equations


trying to find <a|L.S|a>, <a|L.S|b>, <b|L.S|a>, <b|L.S|b> (those are the matrix elements), by expanding L.S as in the equation, and then using the actions of the given operators on the basis vectors .





The Attempt at a Solution



<alpha|beta> = <beta|alpha> = 0

LzSz |a> = Lz |l,m-> Sz |alpha> = hbar m- |l,m-> hbar/2 |alpha> ...

am confused on how to contract with the other matrix terms,

any help much appreciated

 
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izzy93 said:

Homework Statement



If a particle has spin 1/2 and is in a state with orbital angular momentum L, there are two basis states with total z-component of angular momentum m*hbar l L,s,Lz,sz > which can be expressed in terms of the individual states ( l L,s,Lz,sz > = l L,Lz > l s,sz > ) as

l a > = l L, 1/2 , m-1/2 , 1/2 > = l L, m-1/2 > l 1/2, 1/2 > = l L, m-1/2 > l alpha >
l b > = l L, 1/2 , m+1/2 , -1/2 > = l L, m+1/2 > l 1/2, -1/2 > = l L, m-1/2 > l beta >

Using these two states (l a > and l b >) as a basis, show that the matrix representation of the operator L.S is: where L.S = 1/2 ( L+S- + L-S+) + LzSz note all operators here with hats
$$\hat{L}\cdot\hat{S} = \frac{\hbar^2}{2}
\begin{pmatrix}
m-1/2 & \sqrt{(L+1/2)^2 - m^2} \\
\sqrt{(L+1/2)^2 - m^2} & m-1/2
\end{pmatrix}
$$

Homework Equations



trying to find <a|L.S|a>, <a|L.S|b>, <b|L.S|a>, <b|L.S|b> (those are the matrix elements), by expanding L.S as in the equation, and then using the actions of the given operators on the basis vectors.


The Attempt at a Solution



<alpha|beta> = <beta|alpha> = 0

$$\hat{L}_z\hat{S}_z\lvert a \rangle = \hat{L}_z\lvert l,m-\rangle \hat{S}_z\lvert \alpha \rangle = (\hbar m-) \lvert l, m-\rangle \frac{\hbar}{2} |\alpha \rangle$$

am confused on how to contract with the other matrix terms,

any help much appreciated
You have the correct approach. What do the raising and lowering operators do to a state? For instance, what does ##\hat{L}_-## do to ##\lvert l, m \rangle##? You should be able to find this in your textbook if you don't already know.
 
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