- #1

izzy93

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## Homework Statement

If a particle has spin 1/2 and is in a state with orbital angular momentum L, there are two basis states with total z-component of angular momentum m*hbar l L,s,Lz,sz > which can be expressed in terms of the individual states ( l L,s,Lz,sz > = l L,Lz > l s,sz > ) as

l a > = l L, 1/2 , m-1/2 , 1/2 > = l L, m-1/2 > l 1/2, 1/2 > = l L, m-1/2 > l alpha >

l b > = l L, 1/2 , m+1/2 , -1/2 > = l L, m+1/2 > l 1/2, -1/2 > = l L, m-1/2 > l beta >

Using these two states (l a > and l b >) as a basis, show that the matrix representation of the operator

**L.S**is: where

**L.S**= 1/2 ( L+S- + L-S+) + LzSz note all operators here with hats

L.S = Hbar ^2 /2 { (m-1/2) [ (L +1/2)^2 - m^2 ]^1/2

[ (L +1/2)^2 - m^2 ]^1/2 (m-1/2) }

## Homework Equations

trying to find <a|L.S|a>, <a|L.S|b>, <b|L.S|a>, <b|L.S|b> (those are the matrix elements), by expanding L.S as in the equation, and then using the actions of the given operators on the basis vectors .

## The Attempt at a Solution

<alpha|beta> = <beta|alpha> = 0

LzSz |a> = Lz |l,m-> Sz |alpha> = hbar m- |l,m-> hbar/2 |alpha> ...

am confused on how to contract with the other matrix terms,

any help much appreciated