Quantum Tunneling and Heat Distribution in Laser Cavities?

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Discussion Overview

The discussion revolves around the implications of replacing a half-transparent mirror in a laser cavity with a 100% reflective mirror, focusing on quantum tunneling effects, heat distribution, and the efficiency of lasers. Participants explore theoretical and practical aspects of laser operation, including energy transitions and temperature effects.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • One participant questions whether all photons would escape due to quantum tunneling if a 100% reflective mirror were used.
  • Another participant asserts that there are no 100% reflective mirrors and that losses in the laser components would balance the gain, preventing all photons from escaping.
  • A participant explains that increasing reflectivity would lead to more heat generation rather than laser output, suggesting that the mirrors would not melt due to the inefficiency of the laser.
  • One participant proposes that cooling the laser might shorten the wavelength, which is challenged by another who states that the wavelength is determined by atomic or molecular transitions.
  • Another participant emphasizes that while transition energies depend weakly on temperature, the relative intensity of transitions is more significantly affected, particularly in laser diodes.

Areas of Agreement / Disagreement

Participants express differing views on the effects of increasing mirror reflectivity and the relationship between temperature and wavelength in lasers. There is no consensus on the implications of these changes, and the discussion remains unresolved.

Contextual Notes

Participants reference various assumptions about laser efficiency, heat dissipation, and the nature of atomic transitions without resolving the complexities involved in these processes.

Daniel Petka
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What if I replaced the half transparent mirror in a laser cavity with a 100% reflective mirror?
-would all photons escape due to the quantum tunneling effect?
-would the mirrors melt?
Thanks :biggrin:
 
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There are no 100% reflective mirrors. Every component of the laser has some losses. The intensity would increase until the losses match the gain.
 
Ty
 
Usually, lasers are not very efficient at converting input power to laser light. Most of it gets converted to heat, which needs to be dissipated somehow. If you made the reflectivity very high, then the laser would just stop outputting light, and instead would generate a little more heat. It probably wouldn't destroy the mirrors, since the laser wasn't very efficient to begin with, and increasing the heat a little probably won't overtax the heat sinks.

In a laser, you have a laser medium with multiple excited states. For simplicity, let's consider a three state system. G is the ground state. A is the upper state, and B is the middle state. The power supply is connected to some arc source which excites the laser medium to the A and B states. A decays to B faster than B decays to G, so you get a population inversion between B and the G. So, you get lasing for the B to G transition. But the A to B transition photons are basically lost somewhere, and I guess they get converted to heat eventually. If you turn up the reflectivity, you'll reach some steady state field energy in the cavity, and all the extra power gets converted to heat. Since there is no laser power being carried away, the laser medium becomes more excited and you have more A to B transitions creating heat.
 
So cooling the laser should make the wavelength shorter, right?
 
Nope. The wavelength is determined by what atomic or molecular transitions are amplified.
 
Khashishi said:
Nope. The wavelength is determined by what atomic or molecular transitions are amplified.

Well then I suppose you should see some leds or lasers in liquid nitrogen
 
LEDs are not lasers.

The transition energies depend weakly on the temperature, the relative intensity of different transitions (if applicable) depends more on the temperature. That is relevant for LEDs and still notable for laser diodes, for other types of lasers it is a tiny effect. Here is an estimate of 0.3 nm/K for laser diodes.
 

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