- #1
sunrah
- 191
- 22
(please note this is similar to a homework question I have posted but it is not the same and here I am just trying to understand a concept)
In a book I was reading it said
<br /> \Delta^{+} \longrightarrow n + \pi^{+}<br />
is a viable process via the strong force because all that is needed is a down antidown quark pair, which can be provided via the strong force. My question is why? If \Delta^{+} is uud and \Delta^{+}\pi^{+} is udd + u\bar{d} we can see that the right hand side only has one antidown quark therefore there has only been one quark-antiquark pair created. Converting one quark into two only creates one extra particle effectively so I see a deficit on the left hand side.
Please can someone explain
In a book I was reading it said
<br /> \Delta^{+} \longrightarrow n + \pi^{+}<br />
is a viable process via the strong force because all that is needed is a down antidown quark pair, which can be provided via the strong force. My question is why? If \Delta^{+} is uud and \Delta^{+}\pi^{+} is udd + u\bar{d} we can see that the right hand side only has one antidown quark therefore there has only been one quark-antiquark pair created. Converting one quark into two only creates one extra particle effectively so I see a deficit on the left hand side.
Please can someone explain
Last edited:
What you have written does not conserve charge.
